-x^2+120x-3600=0

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Solution for -x^2+120x-3600=0 equation: 



-x^2+120x-3600=0

We add all the numbers together, and all the variables

-1x^2+120x-3600=0

a = -1; b = 120; c = -3600;
Δ = b2-4ac
Δ = 1202-4·(-1)·(-3600)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-120}{-2}=+60$

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